Question

solve this for me -1

Answer 1

Hope this helps you....

Answer 2

Hey friend,
Here is the answer you were looking for:
$\frac{ {4}^{5} \times {a}^{8} {b}^{3} }{ {4}^{5} \times {a}^{5 } {b}^{2} } \\ \\ using \: the \: identity \\ \frac{ {a}^{m} }{ {a}^{n} } = {a}^{m - n} \\ \\ = {4}^{5 - 5} \times {a}^{8 - 5} {b}^{3 - 2} \\ \\ = {4}^{0} \times {a}^{3} {b}^{1} \\ \\ = 1 \times {a}^{3} b \\ \\ = {a}^{3} b$

Hope this helps!!!

@Mahak24

Thanks..
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