Solve this... for me....
Attachments:
Answers
Answered by
1
Let AB is a tree,the broken part is x and the remaining part is y.
CD=distance from the foot =8m
so,y/8=tan 30
y/8=1/root 3
y=8/root 3
then,x/8=sec 30
x/8=2/root 3
x=4root3
now ht. of the tree=x+y=4root 3+8/root 3=20/root 3m(Ans)
CD=distance from the foot =8m
so,y/8=tan 30
y/8=1/root 3
y=8/root 3
then,x/8=sec 30
x/8=2/root 3
x=4root3
now ht. of the tree=x+y=4root 3+8/root 3=20/root 3m(Ans)
Sudipta2002:
Chal haat.. Check in above comments.. I had said mujhe ladkon se baat krna achha nhi lagta.. Can't u understand these lines?
aab samajh gaya toh chup rah na...
issme ajib kya h??achha h na unique hun sabse alag...tumhe kya prblm h ...
Answered by
1
Answer:
13.86 m
Step-by-step explanation:
Let y be the distance of the top of the tree touching the ground from the base of it is 8m
The total hieght of the tree is x+z
=> x / y= tan 30
=> x /8 = tan 30
=> x = 8 * 3-1/2
=> x = 4.62 m (approx)
=> x / z = sin 30
=> z = x / sin30
=> z= 4.62/sin30 = 9.24 (approx)
therefore the total hieght of the tree is x + z = 4.62 +9.24
= 13.86 m (approx )
Similar questions