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(i)AB=AC(given)
AD=AD(common side)
BD=DC(given)
hence, ΔABD≅ΔACD
(ii)∠B=∠C by CPCT(Corresponding parts of congruent triangles)
(iii)Since AD is bisecting BC, ∠ADB=90°(bisector in an isosceles Δ is perpendicular)
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∠ADB=90°(bisector in an isosceles Δ is perpendicular)
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