Question

solve this for me plzz

Answer 1

1) let x=0.666

x=0.6666 ______×10 _eq1

10x=6.666 _eq2

substracting eq2 by eq1

10x-x=6.66-0.66

9x=6

x=2/3

Hence,

0.666=2/3

2) Let both angles be x and y

then

Case I;

x+y = 80° eq1

CaseII,

x-y =20° eq2

Adding eq1 and eq2

x+y =80°

x-y =20°

2x=100

x=50°

then y=30°

3) Suitable identity;

(a-b)(a+b)= a^2 -b^2

Hence,

=2x^2-3^2

=4x-9

x=9/4

4)Area of equilateral triangle= underoot3a

so,

underoot3 ×12

1.7×12

20.4

5)Putting value of x and y

= 6×4

=24

6)(3,0)