Question

Solve this for me plzz.It is a factorisation question.

Answer 1

Hola..!!

24.Sol'n: Let
$x = a + 2b$
Therefore,
$1 - 2(a + 2b) - 3 {(a + 2b)}^{2} \\ = 1 - 2x - 3 {x}^{2} \\ = - 3 {x}^{2} - 2x + 1 \\ = - 3 {x}^{2} - (3 - 1)x + 1 \\ = - 3 {x}^{2} - 3x + x + 1 \\ = - 3x(x + 1) + 1(x + 1) \\ = (x + 1)( - 3x + 1) \\ = ((a + 2b) + 1)( - 3(a + 2b) + 1) \\ = (a + 2b + 1)( - 3a - 6b + 1)$
Do the second one same as the first one.

Hope it'll help u..