solve this fr me plzzz
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you can see that there is a 90° angle so you can easily solve it.
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Hola Friend ✋✋✋
Given :-
AB = AC
BD perpendicular to AC
To prove :-
BD² - DC² = 2 AD . DC
Proof :
Applying Pythagoras theorem in ∆ BAD
AB² = AD² + DB² ........ (1)
AC = AD + DC = AB
SO , IN EQUATION (1)
( AD + DC )² = AD² + DB²
AD² + DC² + 2 AD . DC = AD² + DB²
DC² + 2 AD . DC = DB²
BD² - DC² = 2 AD . DC
HENCE PROVED
HOPE IT HELPS
Given :-
AB = AC
BD perpendicular to AC
To prove :-
BD² - DC² = 2 AD . DC
Proof :
Applying Pythagoras theorem in ∆ BAD
AB² = AD² + DB² ........ (1)
AC = AD + DC = AB
SO , IN EQUATION (1)
( AD + DC )² = AD² + DB²
AD² + DC² + 2 AD . DC = AD² + DB²
DC² + 2 AD . DC = DB²
BD² - DC² = 2 AD . DC
HENCE PROVED
HOPE IT HELPS
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