Question

Solve this friends .

Happy navratri ​

Answer 1

Answer:

$24 {x}^{3} + 46 {x}^{2} + 9x - 9 = 0 \\ \\ roots = > \alpha \: \: . \: \: 2 \alpha \: \: and\: \: 4 \alpha \\ \\ = > 7 \alpha = - \frac{46}{24} \\ \\ \alpha = - \frac{46}{24 \times 7}$

Answer 2

24x3+46 x 2+9x-9=0

Let the roots be a.2a,b

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