Question

solve this given question please​

Answer 1

x^2 + X + 1/√2= 0

x^2+ X + 1/4 + 1/√2 - 1/4 = 0

(X + 1/2)^2 + ( 1/√2 - 1/4 ) = 0

{X + i(1/√2+1/2 -1/4) }{X - i(- 1/√2 + 1/4 + 1/2} =0

{X + i(1/√2+1/4)}*{X - i(3/4 - 1/√2) }= 0

X = - i(1/√2+1/4)} and i(3/4 - 1/√2)

where I is iota