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thus, one pipe will take 5mins and other will take (5+3=8) minutes to fill the cistern
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Answer:
Let the volume of the cistern be V.
Together two pipes take 3 1/13 mins = 40/13
Rate of both the pipes together = V/(40/13)
Let pipes be A and B,
Time taken by A = t mins , So rate = V/t
Time taken by B = t+3 mins, So rate = V/(t+3)
Combined rate = V/t + V/(t+3)
We already know that combined rate = V/(40/13)
Equating both ,
V/t + V/(t+3) = V/(40/13)
1/t + 1/(t+3) = 13/40
(t+3+t) / t(t+3) = 13/40
(2t + 3)/ (t^2+3t) = 13/40
80t + 120 = 13t^2 + 39t
13t^2 - 41t - 120 = 0
The quadratic equation yields two roots :
5 and -1.846 , since time cannot be negative
Time taken by pipe A = 5 mins
Time taken by pipe B = 5+3 = 8 mins
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Nice answer