solve this help me this is maths questions
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(2+root3)(3+root2)÷(3-root2)(3+root2)
=(5+2root2+3root3+root6)÷((3)^2-(root2)^2)
=(5+2root2+3root3+root6)÷(9-2)
=(5+2root2+3root3+root6)÷7
=5+2root2+3root3+root6/7...ans
Hope it helps...
jatinkumar99:
@bhai @galat @h
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Answer:
BHAI KARNA JARURI H
Step-by-step explanation:
First, multiply the denominator.
Bhai mera to ye aa raha he
Agar sahi he to
Nahi to raha ne de na
And
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