Question

solve this help me this is maths questions​

Answer 1

(2+root3)(3+root2)÷(3-root2)(3+root2)

=(5+2root2+3root3+root6)÷((3)^2-(root2)^2)

=(5+2root2+3root3+root6)÷(9-2)

=(5+2root2+3root3+root6)÷7

=5+2root2+3root3+root6/7...ans

Hope it helps...

Answer 2

Answer:

BHAI KARNA JARURI H

Step-by-step explanation:

$\huge\red{\underline{\green{Answer}}}$

First, multiply the denominator.

$\frac{2 + \sqrt{3} }{3 - \sqrt{2} } \times \frac{3 + \sqrt{2} }{3 + \sqrt{2} }$

$\frac{(2 + \sqrt{3} )(3 + \sqrt{2})}{ {3}^{2} - { \sqrt{2} }^{2} }$

$\frac{6 + 2 \sqrt{2} + 3 \sqrt{3} + \sqrt{6} }{9 - 2}$

$\frac{6 + 2 \sqrt{2} + 3 \sqrt{3} + \sqrt{6} }{7}$

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