Question

Solve this. I challenge you. I will follow up you.​

Answer 1

$\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R}}}}$

=>(x-10)(x-362)>0

$\huge{\fbox{\fbox{\green{\mathfrak{Explanation}}}}}$

=>√2x+5+√x-1 > 8

=> √2x+5 > -√x-1+8

Squaring on B.S

=>(√2x+5)^2 > (-√x-1+8)^2

=>2x+5 > x-1+64-16√x-1

=>16√x-1 > -2x-5+x-1+64

=>16√x-1 > -x+58

Again squaring on B.S

=>(16√x-1)^2 > (-x+58)^2

=>256(x-1) > x^2+3364-116x

=>256x-256 > x^2-116x+3364

=>x^2 - 372x + 3620 > 0

=>X^2-362x-10x+3620 > 0

=>X(x-362)-10(x-362) > 0

=>(x-10)(x-362) > 0

Answer 2

Answer:

=>√2x+5+√x-1 > 8

=> √2x+5 > -√x-1+8

Squaring on B.S

=>(√2x+5)^2 > (-√x-1+8)^2

=>2x+5 > x-1+64-16√x-1

=>16√x-1 > -2x-5+x-1+64

=>16√x-1 > -x+58

Again squaring on B.S

=>(16√x-1)^2 > (-x+58)^2

=>256(x-1) > x^2+3364-116x

=>256x-256 > x^2-116x+3364

=>x^2 - 372x + 3620 > 0

=>X^2-362x-10x+3620 > 0

=>X(x-362)-10(x-362) > 0

=>(x-10)(x-362) > 0

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