Question

Solve this, I need it's very urgent do these four sums only it's very urgent.........​

Answer 1

5. Given ratios = 2:3:4

Assume each angle is a multiple of x

Therefore 2x + 3x + 4x = 180 (Angles on a straight line)

9x = 180

x = 20

Therefore: BOC = 40, COD = 60, DOA = 80

6. 30 + 100 + x + 150 = 360 (Angles around a point)

x + 280 = 360

x = 80

7. 2x + x + 4x + 2x = 360 (Angles around a point)

9x = 360

x = 40

Therefore: AOB = 40, BOC = 80, COD = 80, DOA = 160,

8. x + 3x + 86 + 90 + 112 = 360

4x + 288 = 360

4x = 72

x = 18

Therefore: DOE = 18, EOA = 54

Answer 2

Answer:

5

1. let the angles be in the ratio
2. 2x, 3x, 4x
3. then by angle sum property
4. 2x+3x+4x=180
5. 9x=180
6. x=180/9
7. x=20
8. <BOC=2X
9. <BOC=2×20
10. <BOC=40
11. <COD=3X
12. <COD=3×20
13. <COD=60
14. <DOA=4X
15. <DOA=4×20
16. <DOA=80

6

1. <COB+BOA=180
2. 100+x=180
3. x=180-100
4. x=80

7

1. AOB+BOC+COD+DOA=360
2. 2x+3x+x+4x=360
3. 10x=360
4. x=36
5. AOB=X
6. AOB=36
7. BOC=2X
8. BOC=36×2
9. BOC=72
10. COD=3X
11. COD=36×3
12. COD= 108
13. DOA=4X
14. DOA=4×36
15. DOA=144

8

1. 112+90+86+X+3X=360
2. 4X+298=360
3. 4X=360-298
4. 4X=62
5. X=62/4
6. EOA=X
7. EOA=62/4
8. DOE=3X
9. DOE=3×62/4
10. DOE=46.5