Question

solve this i will mark he or she brainliest

Answer 1

Heyy Dear❤
Here is u r Ans ➡

C) ➡
$= (2x + \frac{1}{2x } ) {}^{3} - (2x - \frac{1}{2x} ) {}^{3}$

$= using \: > \: a {}^{} - b {}^{3} = (a - b)(a {}^{2} + ab + b {}^{2} )$

$= (2x + \frac{1}{2x} - (2x - \frac{1}{2x} )) \times ((2x + \frac{1}{2x} ) {}^{2} + (2x + \frac{1}{2x} ) \times (2x - \frac{1}{2x} ) + (2x - \frac{1}{2x} ) {}^{2} )$

$= (2x + \frac{1}{2x} - 2x + \frac{1}{2x} ) \times (( \frac{4x {}^{2} + 1}{2 x} ) {}^{2} ) + \frac{4x {}^{2} + 1}{2x} \times \frac{4x {}^{2} + 1}{2x} + ( \frac{4x {}^{2} - 1 }{2x} ) {}^{2} )$

$= \frac{2}{2x} \times ( \frac{(4x {}^{2} + 1) {}^{2} }{4x {}^{2} } + \frac{(4x {}^{2} + 1) \times (4x {}^{2} - 1)}{4x {}^{2} } + \frac{(4x {}^{2} - 1) }{4x {}^{2} } )$

$= reduce \: 2 \: or \: 2x \:$

$= then. \: \: using > \: (a - b)(a + b) = a {}^{2} - b {}^{2}$

$= \frac{1}{x} \times ( \frac{(4x {}^{2} + 1) {}^{2} }{4x {}^{2} } + \frac{16x {}^{4} - 1}{4x {}^{2} } + \frac{(4x {}^{2} - 1) {}^{2} }{4x {}^{2} }$

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Hope This Helps u ☺.