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in a right angled triangle ACB
Hypotenuse= AB= 13 cm.
BC= 5 cm
now,
by pythagoras theorem,
AC= 12 cm.
now,
cos B= CB/AB= adjacent side/ hypotenuse.
cos B = 5/13
cos2 B= 25/169.....(1)
now,
sin A = CB/ AB
= 5/13
sin2 A = 25/169....(2)
now from (1) &(2),
cos2B + sin2A= 25/169+25/169
= 25+25/169
= 50/169
Caroline134:
thank you bro
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