Solve this ICSE class 10 mathematics question.
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Answered by
11
HEY MATE.......!
HERE'S THE ANSWER....
Given :
AB and CD are the chords of the circle. they are produced to meet at O.
CD = 2cm.
DO = 6cm.
BO = 3cm.
To prove:
ODB ~ OCA
Proof:
In triangles ODB and OCA
<DOB = <COA
<ACD = <DBO [property of angle of cyclic quadrilateral]
ODB ~ OCA
Hence proved.
--------------------------------------------
HOPE IT HELPS...
PLEASE FOLLOW ME....
THANK YOU
BY SHIVAM SHAURYA
HERE'S THE ANSWER....
Given :
AB and CD are the chords of the circle. they are produced to meet at O.
CD = 2cm.
DO = 6cm.
BO = 3cm.
To prove:
ODB ~ OCA
Proof:
In triangles ODB and OCA
<DOB = <COA
<ACD = <DBO [property of angle of cyclic quadrilateral]
ODB ~ OCA
Hence proved.
--------------------------------------------
HOPE IT HELPS...
PLEASE FOLLOW ME....
THANK YOU
BY SHIVAM SHAURYA
shivamshaurya:
dear you can solve the rest of the problems by using the similarity
calculate ab
okay
the mean part of the question I have done......please dear.....try to solve rest of the problem
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ok
Answered by
2
AB and CD are the chords of the circle. they are produced to meet at O.
CD = 2cm.
DO = 6cm.
BO = 3cm.
To prove:
ODB ~ OCA
Proof:
In triangles ODB and OCA
<DOB = <COA
<ACD = <DBO [property of angle of cyclic quadrilateral]
ODB ~ OCA
Hence proved.
CD = 2cm.
DO = 6cm.
BO = 3cm.
To prove:
ODB ~ OCA
Proof:
In triangles ODB and OCA
<DOB = <COA
<ACD = <DBO [property of angle of cyclic quadrilateral]
ODB ~ OCA
Hence proved.
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