Math, asked by Gopeshtiwari34, 11 months ago

Solve this if u can ?​

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Answered by vaishnavitiwari1041
3

Here's Your Answer

 \tan( \alpha  +  \beta )  =  \frac{ \tan( \alpha )  +  \tan( \beta ) }{1 -  \tan( \alpha ) \tan( \beta )  }  \\  \\  =  \frac{ \frac{1}{3}  +  \frac{1}{2} }{1 -  \frac{1}{3} \times  \frac{1}{2}  }  \\  \\  =  \frac{ \frac{2 + 3}{6} }{ \frac{6 - 1}{6} }  =  \frac{ \frac{5}{6} }{ \frac{5}{6} }  \\  \\  =  \frac{5}{6}  \times  \frac{6}{5}  = 1 \\  \\  = 1 \\  \\  = 45

➡ As tan = 1 will be on 45°

Hope it helps ✨❤

Answered by Anonymous
0

Answer:

tiwari ji

Step-by-step explanation:

hey msg karo mujhe

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