Question

solve this if you can​

Answer 1

Initially the distance covered by the car will be equal to the distance covered by the bus

speed =50 m/s

speed (v)=distance/time

distance (s)=50×t

As per the formula,

$s = ut + \frac{1a {t}^{2} }{2}$

$50t = \frac{1a {t}^{2} }{2}$

$t = \frac{50 \times 2}{5} \\ t = \frac{100}{5} \\ t = 20sec$

distance at which the bus overtakes the car

=50×t

=50×20

=1000m

As per the formula,

v² =u² +2 as

v² = 2 ×5 ×1000

v² =10000

v=100 m/s