Solve this if you can do it. don't give meaningless answers I will report
Answers
Step-by-step explanation:
Given :-
Sum of the numerical values of volume , area and perimeter of a cube is 504.
To find :-
Find the length of the side of a cube ?
Solution :-
Let the length of the side of a cube is a units
Surface area of a cube = 6a² sq.units
Volume of a cube = a³ cubic units
Perimeter of a cube = 12a units
Since the edges in a cube = 12
Given that
Sum of the numerical values of volume , area and perimeter of a cube = 504.
=> a³+6a²+12a = 504
=> a³+6a²+12a-504 = 0
=> a³-6a²+12a²-72a+84a-504 = 0
=> (a³-6a²)+(12a²-72a)+(84a-504 )= 0
=> a²(a-6)+12a(a-6)+84(a-6) = 0
=> (a-6)(a²+12a+84) =0
=> (a-6) = 0 or a²+12a+84 = 0
No real roots for a²+12a+84 = 0
So, a -6 = 0
=> a=6
The edge = 6 units
a²+12a+84 = 0
The value of discriminant = b²-4ac
=> 12²-4(1)(84)
=> 144-336
=>- 192<0
So it has no real roots
So a = 6 units
Answer :-
The length of the edge of the cube is 6 units
Used formulae:-
- Surface area of a cube = 6a² sq.units
- Volume of a cube = a³ cubic units
- Perimeter of a cube = 12a units
- a = edge of the cube
- A cube has faces = 6 , edges = 12 , vertices = 8
Answer:
Sorry I am answering it here and this is the solution of your another question asked.
pls mark as brainlist.
a humble request.
