SOLVE THIS IF YOU CAN ...
If possible, you may show the method.
It's easy
( Hint : It's an equation )
Just follow the attachment..
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Anonymous:
umm, both are brainliest :-).
Answers
Answered by
9
Hello,
[This is my 2nd time to help ya ^_^]
Here's the answer :-
Sum of 3 red flowers = 60
=> Sum of one red flower = 60/3 = 20
_______________________________
Sum of red flower + 2 purple flowers = 30
=> 20 + sum of two purple flowers = 30
=> Sum of two purple flowers = 30-20 = 10
=> Sum of one purple flower = 10/2 = 5
_______________________________
Sum of purple flower - 2 sunflower = 3
=> 5 -sum of two sunflower = 3
=> Sum of two sunflower = 5-3 = 2
=> Sum of 1 sunflower = 1
_______________________________
Following BODMAS,
1 + 20 x 5 = 1 + 100 = 101
_______________________________
GIVEN ANSWER = 101
hope it helped :-)
#Supersonu
#Brainly Benefactor
[This is my 2nd time to help ya ^_^]
Here's the answer :-
Sum of 3 red flowers = 60
=> Sum of one red flower = 60/3 = 20
_______________________________
Sum of red flower + 2 purple flowers = 30
=> 20 + sum of two purple flowers = 30
=> Sum of two purple flowers = 30-20 = 10
=> Sum of one purple flower = 10/2 = 5
_______________________________
Sum of purple flower - 2 sunflower = 3
=> 5 -sum of two sunflower = 3
=> Sum of two sunflower = 5-3 = 2
=> Sum of 1 sunflower = 1
_______________________________
Following BODMAS,
1 + 20 x 5 = 1 + 100 = 101
_______________________________
GIVEN ANSWER = 101
hope it helped :-)
#Supersonu
#Brainly Benefactor
Answered by
13
hi friend
here is your answer
In 1st case there are 3 roses
let , each rose to be R
then ATQ.
R + R + R = 60
3R = 60
R = 60/3
R= 20
in 2nd case there are 2 flowers with violet and yellow colour in them + 1rose
let , each violet and flower be V
Then , ATQ
R + V + V = 30
as above ,
we already know that one R = 20
now substitute here
20 + 2V = 30
2V = 30-20
2V = 10
V = 10/2
V = 5
now last equations
there are 2 sunflowers and one violet flower
let each sunflower toz be S
=> V - 2S = 3
as we got in above equation V = 5
now , here,
5 - 2S = 3
2S = 5-3
2S = 2
S = 1
now coming to the main question
they asked us to find the value of
S + R × V = ???
we got all the values above
so now substitute them
1 + 20 × 5
according to BODMAS
1 + 100
101
SO FINALLY THE ANSWER IS 101
S + R × V = 101
HAVE A NICE DAY
HOPE IT HELPS U
here is your answer
In 1st case there are 3 roses
let , each rose to be R
then ATQ.
R + R + R = 60
3R = 60
R = 60/3
R= 20
in 2nd case there are 2 flowers with violet and yellow colour in them + 1rose
let , each violet and flower be V
Then , ATQ
R + V + V = 30
as above ,
we already know that one R = 20
now substitute here
20 + 2V = 30
2V = 30-20
2V = 10
V = 10/2
V = 5
now last equations
there are 2 sunflowers and one violet flower
let each sunflower toz be S
=> V - 2S = 3
as we got in above equation V = 5
now , here,
5 - 2S = 3
2S = 5-3
2S = 2
S = 1
now coming to the main question
they asked us to find the value of
S + R × V = ???
we got all the values above
so now substitute them
1 + 20 × 5
according to BODMAS
1 + 100
101
SO FINALLY THE ANSWER IS 101
S + R × V = 101
HAVE A NICE DAY
HOPE IT HELPS U
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