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5.NaCl+CO2+NH3=NH3Cl+NaHCO3
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☞ Given,
initial velocity of ball, u=0
Final velocity of ball, v=?
Distance through which the balls falls, s=20m
☞ Acceleration
a=10 \: ms −2a=10ms−2
Time of fall, t=?
☞ We know
v {}^{2} - u {}^{2} = 2asv
2
−u
2
=2as
v {}^{2} −0=2×10×20=400v
2
−0=2×10×20=400
v=20msv=20ms
☞ Now using v=u+at we have
20=0+10×t20=0+10×t
t=2st=2s
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