solve this in a paper then send the answer please
For class 9th .
don't give unwanted answers plz.....
answer fast pls......
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Area of triangle DRC
= 1/2× DC × (x)
Area of triangle DPC
= 1/2 × DC × (×)
Hence Ar(DRC) = Ar(DPC)
Similarly Ar(ADC) = Ar(BDC)
Adding the above two equations
we get
Ar(ARC) = Ar(BDP)
I hope this answer help you
= 1/2× DC × (x)
Area of triangle DPC
= 1/2 × DC × (×)
Hence Ar(DRC) = Ar(DPC)
Similarly Ar(ADC) = Ar(BDC)
Adding the above two equations
we get
Ar(ARC) = Ar(BDP)
I hope this answer help you
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KarupsK:
Mark this answer as brainliest answer
Answered by
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hope this will help if not contact me
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