Question

solve this inequation ASAP​

Answer 1

$\huge\bf{\red{\overbrace{\underbrace{\purple{Given:}}}}}$

★$12+1\dfrac{5}{6}x ≤ 5 + 3x$

$\huge\bf{\red{\overbrace{\underbrace{\purple{To\:\:Find:}}}}}$

★Set of possible values of x.

$\huge\bf{\red {\overbrace{\underbrace{\purple{Answer:}}}}}$

We have,

$\implies 12+1\dfrac{5}{6}x ≤ 5$

$\implies 12+\dfrac{11x}{6}≤ 5$

$\implies 12-5 ≤ 3x - \dfrac{11x}{6}$

$\implies 7 ≤ \dfrac{18x - 11x }{6}$

$\implies 7 ≤ \dfrac{7x}{6}$

$\implies x ≥ \dfrac{6\times 7}{7}$

$\implies x ≥ \dfrac{6\times \cancel{7}}{\cancel{7}}$

${\underline{\boxed{\purple{.\degree . x ≥ 6 }}}}$

Therefore x can sustain all values greater than Or equal to 6 .So,

$\huge\green{\boxed{\red{x \epsilon [6, \infty) }}}$