Question

Solve this integral.
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Answer 1

Answer:

We know that

e[log x]=x

= cosec square x -1

since cosec square x - cot square x = 1

Now L e [ 2 log cot x ] dx

L { cosec square x - 1 } dx

L cosec square dx - L dx

= - cot x -x+ c

Thus option 4 is correct .

Thankyou for this beautiful & easy question'