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Given three points (1,2),(3,−4)and(5,−6)
Let the coordinates o centre be O(h,k)
The distance from the centre to a point on the circumference is equal to radius.
∴ OA=OB=OC
From distance formula
OA2=OB2
(h−1)2+(k−2)2=h−3)2+(k+4)2h2−2h+1+k2−4k+4=h2−6h+9+k2+8k+16
−2h−4k+5=−6h+8k+254h−12k=20⟹h−3k=5⟶
(1)OB2=OC2
(h−3)2+(k+4)2=(h−5)2+(k+6)2
h2−6h+9+k2+8k+16=h2−10h++25+k2+12k+36
−6h+8k+25=−10h+12k+61
⟹4h−4k=36⟹h−k=9⟶(2)
=−2k=−4h−3k=5−h±k=−9
∴k=2∴h=11
∴ The Coordinates are (h,k)=(11,2)
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