Question

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Answer 1

Explanation:

The ball is released from top of tower.

The ball takes T seconds to reach the ground.

Position of ball (height of tower)

h = 1/2gT²

Position of ball at T/3 seconds

h' = 1/2g(T/3)²

h' = 1/2gT²/9

h' = 1/9 × 1/2gT²

h' = 1/9 × h

h' = h/9

h' is the distance covered by the ball in T/3 seconds.

Total height = h

Distance covered, h' = h/9

Therefore, Position of ball

= h - h'

= h - h/9

= 8h/9

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Answer 2

Answer:

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Explanation:

We know that s=ut+12>2,orh=12gT2〈.U=0) 

now for T/3 second , vertical distance moved is given by 

h′=12g(T3)2⇒h′=12×gT29=h9 

∴ Position of ball from ground =h-h9=8h9.