Math, asked by pranay9018, 1 month ago

Solve this it's urgent don't spam if spammed u may get reported

it is not a communication language it is factorials related to mathematics​

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Answers

Answered by TheGodWishperer
5

To find :-

Unit place of 2!+ 3! +... 100!

Solution:-

let's sum up

2!= 1x2=2

3!=1x2x3=6

4!=1x2x3x4=24

5!=1x2x3x4x5=120

Now after 4! a zero is seen in last digit of 5! Hence now upto infinite the last digit of factorial will always be zero for example 6!=720 and 7!=5040.

It is clear that unit digit will be decided by the sum of 2!+3!+4! because they are the only number ending with non zero unit place

Hence once place digit will be

2!+3!+4!= 2+6+24=32

\Large\mathtt\red{\boxed{Answer=2}}

Answered by npranay2021
1

Answer:

2

Step-by-step explanation:

To find :-

Unit place of 2!+ 3! +... 100!

Solution:-

let's sum up

2!= 1x2=2

3!=1x2x3=6

4!=1x2x3x4=24

5!=1x2x3x4x5=120

Now after 4! a zero is seen in last digit of 5! Hence now upto infinite the last digit of factorial will always be zero for example 6!=720 and 7!=5040.

It is clear that unit digit will be decided by the sum of 2!+3!+4! because they are the only number ending with non zero unit place

Hence once place digit will be

2!+3!+4!= 2+6+24=32

\Large\mathtt\green{\boxed{Answer=2}}

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