Math, asked by Anonymous, 7 months ago

SOLVE THIS!!! ITS URGENT!!​

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Answers

Answered by angelinjk
1

Step-by-step explanation:

18)

N(s)= (hhh, hht, hth, htt, ttt, tth, tht, thh)

Let A be the event of getting atleast two heads. (two heads and above).

A = (hht,hth,thh,hhh)

n(A) = 4.

p(A) = n(A) \ n(S)

=4/8

=1/2

Let B be the event of getting atmost two heads.(two heads,one head,no head).

B= (hht,hth,thh,htt,tth,tht,ttt)

n(B)=7

p(B)=n(B)/n(S)

=7/8

Let C be the event of getting exactly two heads.

C=(hht,hth,thh).

n(C)=3

p(C)=n(C)/n(S)

=3/8.

Hope this will be usefull for you!

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