Math, asked by babbbbbu, 1 year ago

solve this last problem ​

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Answered by Anonymous
4

\huge{Answer}

2( \frac{2x - 1)}{x + 3} ) - 3(  \frac{x + 3}{2x - 1}  ) = 5

Verify

 \frac{a}{b}  =  \frac{1}{ \frac{b}{a} }

2( \frac{2x - 1)}{x + 3} ) - 3( \frac{1}{ \frac{2x - 1}{x + 3} } ) = 5

2t-3+1/t =5

t=3

t=1/2

 \frac{2x - 1}{x + 3}  = 3

 \frac{2x - 1}{x + 3}  =  \frac{1}{2}

x =  - 10

x =  -  \frac{1}{5}

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