Question

solve this linear equation​

Answer 1

Please mark as brainliest

Answer 2

$\bf{6\dfrac{1}{3} - \dfrac{2 - 7}{3} = \dfrac{4x - 2}{5}}$

$\longmapsto\bf{\dfrac{19}{3} - \dfrac{(-5)}{3} = \dfrac{4x - 2}{5}}$

$\longmapsto\bf{\dfrac{19 + 5}{3}= \dfrac{4x - 2}{5}}$

$\longmapsto\bf{\dfrac{24}{3} = \dfrac{4x - 2}{5}}$

$\longmapsto\bf{8 \times 5 = 4x - 2 }$

$\longmapsto\bf{40 + 2 = 4x }$

$\longmapsto\bf{x = \dfrac{42}{4}}$

$\longmapsto\bf{x = \dfrac{21}{2} }$

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