solve this linear equation ;- n-3 / 2 = 1/5 = n - 4n =1 / 3
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Step-by-step explanation:
n/4+6
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Step-by-step explanation:
n−2, 4n−1, 5n+2 are in A.P.
First term, a1 = n−2
Second term, a2 = 4n−1
Third term, a3 = 5n+2
Common difference (difference of two consecutive terms),
d=a2 −a1 = a3 −a2
4n − 1 − (n−2) = 5n + 2 − (4n − 1)
4n − 1− n + 2 = 5n + 2 − 4n + 1
3n + 1 = n + 3
2n = 2
n = 1
So, a1 = n − 2 = 1 − 2 = −1
a2 = 4n − 1 = 4 − 1 = 3
and d = a2 - a1 = 3 − ( −1) = 4
nth term of an AP is ,
an=a+(n−1)d
where,
a=first term
d= common difference
Therefore,
a4 = a + 3d = −1 + 12 = 11
a5 = a + 4d = −1 + 16 = 15
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