Solve this linear equation please tomorrow is my exam
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Let 1/x+y be 'u' and 1 / x-y be 'v'
our Equation become:
=>5u +3v=4---× 2
=>2u+5v= 27/5-----×5
Our new Equation obtained:
10u +6v=8
10u+25v=27
_______________
-19v=-19
v= 1
Now,put v's value into this equation to obtain I'd value
=>5u+3v=4
=>5u +3= 4
=>5u= 1
=>u=1/5
u=1/5
Now,we have let 1/x+y = u & 1/x-y= v
Now , equate the term
=>1/x+y= 1/5
=>5= x+y ---(1)
=>1/x-y= v
=>1/x-y= 1
=>x-y= 1----(2)
Adding Equation 1 and 2
=>x+y+x-y=6
=>2x=6
=>x=3
=>5=x+y
=>5= 3+y
=>y=2
we get x= 3 & y= 2
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