Solve This Linear Equatiuon:
8j+3<2(7-j)
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15
Answer:
The Answer is:
j<1.1
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0
Answer:
3.2 Factoring 49j2 - 28j + 4
The first term is, 49j2 its coefficient is 49 .
The middle term is, -28j its coefficient is -28 .
The last term, "the constant", is +4
Step-1 : Multiply the coefficient of the first term by the constant 49 • 4 = 196
Step-2 : Find two factors of 196 whose sum equals the coefficient of the middle term, which is -28 .
-196 + -1 = -197
-98 + -2 = -100
-49 + -4 = -53
-28 + -7 = -35
-14 + -14 = -28 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -14 and -14
49j2 - 14j - 14j - 4
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