solve this log
(0.050)
(0.0202
sanjeevkumarjhs988:
youuuu
youu
sorry
I was not knowing
Answers
Answered by
1
Explanation:
1) log(0.050)
= log(5 x 10^-2)
= log(5) + log(10^-2)
= log(5) + (-2)log(10)
= 0.7 - 2
= -1.3
2)log(0.0202)
=log(2.02 x 10^-2)
= log(2.02) + log(10^-2)
= 0.305 + (-2)
= 0.305 - 2
= -1.695
{If bases of log are 10}
bro log 5 se 0.7 kaise aya tell me pls
I round off it so. Actual value (0.6989 ). So I take 0.7
If u have log table then see 5 in zero and zero
ok thks
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