solve this ....<br /><br
/>Rationalize the denominator of<br /> √3 - √2 / √3 + √2
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=> √3 - √2 / √3 + √2 x √3 - √2/√3 - √2
=> (√3 - √2)^2/(√3)^2 - (√2)^2
[a-b]^2= a^2+b^2-2ab
=> (√3)^2 +(√2)^2-2.√3.√2/3-2
=> 3+2-2√6/1
=> 5-2√6
In this type of questions, at first we multiply the denominators and numerators by opposite sign and same as number given in denominators.
After, that with proper calculation we find out our results.
Be Brainly
=> (√3 - √2)^2/(√3)^2 - (√2)^2
[a-b]^2= a^2+b^2-2ab
=> (√3)^2 +(√2)^2-2.√3.√2/3-2
=> 3+2-2√6/1
=> 5-2√6
In this type of questions, at first we multiply the denominators and numerators by opposite sign and same as number given in denominators.
After, that with proper calculation we find out our results.
Be Brainly
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