Question

solve this mate plzz​

Answer 1

Answer:

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The A.P. is 3,5,7,9,......

Hope the answer helps.............

Please mark it as the brainliest.....

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Step-by-step explanation:

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Let in an AP

First-term = a

Common difference = d

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9th term = 19

a + 8d = 19............................................................(1)

19th term =3 * (6th term)

a + 18d = 3 ( a + 5d )

a + 18d = 3a + 15d

0 = 3a + 15d - a - 18d

2a - 3d = 0.............................................................(2)

subtract (2) from 2 * (1)

-19d = -38

d = 2

substitute d = 2 in (1)

a = 3

∴a = 3, d = 2

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required AP is

3,5,7,9.........

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Answer 2

Step-by-step explanation:

a+18d= 3(a+5d)-given

a+8d=19--given

a+18d= 3a+15d

2a-3d=0--eq1

a+8d=19--eq2

multiply eq2 with 2

2a+16d=38

2a-3d=0

19d=38

d=38/2

d=2

a+8*2=19

a+16=19

a=3

so ap is 3,5,7,9....