Question

solve this mate plzzz ​

Answer 1

given three zeros of cubical equation

(2+ ✓5)/2 , (2 - ✓5)/2 &4

roots sum is (2+✓5+2-✓5) 2 + 4=6

sum products of two consecutive numbers

=(2+✓5)(2-✓5)/4+(2+✓5)/2×4+(2-✓5)/2×4=-1/4 + 4+2✓5+4-2✓5

=8-1/4=31/4

roots products= (2+✓5)(2-✓5)×4/4=-1

here is equation

x³- (sum of roots)x² + (sum of products of two roots x- products of root =0

x³ - 6x² +31/4x +1 = 0

hope this answer is helpful!

hey Maine wo I'd log out kardi h

this is my new I'd

Answer 2

Answer:

Please find the attachment