solve this math fast plzzzz
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In trapezium ABCD -
AB ।। CD.
When ab।। cd and ad is the transversal then,
< a + <d = 180° ( co - interior angles are supplementary)
55 °+ <d = 180°
<d = 180 - 55 = 125°
When ab।। cd and bc is the transversal -
Then,
<b + <c = 180°
70 ° + <c = 180°
<c = 180 - 70 = 110°
Hence <d = 125, <c = 110°
shashanksharma101:
nice explanation
Answered by
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✌✌HEY there here's ur answer,
➕answer: from the figure it is clear that
Angle B+ Angle C= 180
then
Angle C = 180- angle B
Angle C= 180-70= 110'
similarly,,,
Angle A+ Angle D= 180
Angle D= 180- Angle A
Angle D = 180- 55= 125'
hence, angle C= 110'
angle D= 125'
if u have doubt in the answers just check them by adding
, such that , we know that, sum of angles of any polygon= 360
from the figure
A + B + C+ D= 55+70+110+125= 360.
⏹⏹hope it helps u⏹⏹
➕answer: from the figure it is clear that
Angle B+ Angle C= 180
then
Angle C = 180- angle B
Angle C= 180-70= 110'
similarly,,,
Angle A+ Angle D= 180
Angle D= 180- Angle A
Angle D = 180- 55= 125'
hence, angle C= 110'
angle D= 125'
if u have doubt in the answers just check them by adding
, such that , we know that, sum of angles of any polygon= 360
from the figure
A + B + C+ D= 55+70+110+125= 360.
⏹⏹hope it helps u⏹⏹
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