Question

Solve This Mathematical Statement.
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Answer 1

Answer:

a)

a= $\frac{7}{-9}$ = $\frac{-7}{9}$

b = $\frac{-6}{7}$

a + b =$\frac{-7}{9}$  + $\frac{-6}{7}$

= $\frac{-49 -54}{63}$

= $\frac{-103}{63}$

a - b = $\frac{-7}{9}$  - $\frac{-6}{7}$

= $\frac{-7}{9}$  + $\frac{6}{7}$

=  $\frac{-49 +54}{63}$

= $\frac{5}{63}$  

So, $\frac{-103}{63}$ ≠ $\frac{5}{63}$  

∴, a - b ≠ a + b

Hence, proved

b)

a =  $\frac{13}{15}$

b =  $\frac{-7}{13}$

a + b =    $\frac{13}{15}$ + $\frac{-7}{13}$

=  $\frac{169 - 105}{195}$

=  $\frac{64}{195}$

a - b =  $\frac{13}{15}$ - $\frac{-7}{13}$

=  $\frac{13}{15}$ + $\frac{7}{13}$

= $\frac{169 + 105}{195}$

= $\frac{274}{195}$

So, $\frac{64}{195}$ ≠ $\frac{274}{195}$

∴, a - b ≠ a + b

Hence, proved

Hope it helps!

Answer 2

Answer:

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