Question

solve this maths.......................​

Answer 1

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Fill in the blanks to factorise polynomial

$2m^{2} +5m-3$

$=2m^{2} +[.........]......3$

$=2m[.........]-1[m+3]$

$=[2m-1][.........]$

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The missing digits.

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$2m^{2} +5m-3$

Consider the form $x^{2} +bx+c$. Find a pair of integers whose product is $c$ and sum is $b$. In this case, we have to find a pair of integers whose product is $[2×(-3)]=(-6)$ and sum is $5$.

The integers are $6$ and $(-1)$.

$2m^{2} +5m-3$

$=2m^{2} +6m-1m-3$

We can take $2m$ common from $(2m^{2} +6m)$ and $(-1)$ from $(-1m-3)$.

$2m^{2} +6m-1m-3$

$=2m(m+3)-1(m+3)$

We can take $(m+3)$ as common.

$2m(m+3)-1(m+3)$

$=(2m-1)(m+3)$

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$2m^{2} +5m-3$

$=2m^{2} +[6m-1m]-3$

$=2m[m+3]-1[m+3]$

$=[2m-1][m+3]$

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The missing digits are -

$2m^{2} +5m-3$

$=2m^{2} +[6m-1m]-3$

$=2m[m+3]-1[m+3]$

$=[2m-1][m+3]$

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