Question

solve this maths problem please​

Answer 1

As AB is parallel to CD the angle p is equal to angle R. As angle p is 90° the angle of R is also 90°. Then x will be 90-65=25°.

As the sum of the angles in a triangle is 180° , z= 65°.

Angle of a linear line is 180 so y=115°

Answer 2

angle PRQ=90°

angle QRC+angleQRP=angle PRQ

65+ x =90°

x=90-65

x=25°

sum of Angles in∆ = 180°

x+z+ anglePQR=180°

25+z+90=180

115+z=180

z=180-115

z=65°

angle on straight line =180°

y+z=180

y+65=180

y=180-65

y=115

x=25°

y=115°

z=65°