solve this maths ques unnecessary answer will be reported
Answers
Step-by-step explanation:
Hey! I can’t find the answer currently as I don’t have access to pen and paper, I can tell you the method to solve it :)
First you need to take the average of the two (add both and divide by 2)
and then the number that u get is one of the 3 answers...
Now continue the same process by using this number that you got as average and any one of the numbers from the question and find it’s average again.... That gives u two numbers
now once again, solve by finding the average of the newly formed number and any one Of the numbers in the question...
Bravo!
NOW THERE IS ANOTHER METHOD
You can find the L.C.M of the two denominators (3,7) which is 21. Multiply the first fraction by (7/7) so that the denominator that you get for both fractions is 21
Later You will find two different numerators... Say x and y
now u can easily find three numbers between two integers X and Y... Find these three and then input the denominator 21 WITHOUT FAIL
for eg. 3/4 and 4/3...
4 and 3 denominators have LCM = 12..
To get same fraction in both, we need to do this
- 3/4 = 9/12
- 4/3 = 16/12
Now find three numbers between 9 and 16.. I will take 10, 12, 15
Therefore the req. Fractions are 10/12, 12/12 and 15/12
Wherever possible, try to lower the answer fractions in the simplest form
Have a Great Day :)