solve this maths question pls
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Hey!!
Your answer is......
As they are in A. P. so,
a1=4k+8, a2=2k^2+3k+6, a3=3k^2+4k+4
Commom difference =a2-a1
2k^2+3k+6-(4k+8)
2k^2+3k+6-4k-8
2k^2-k-2 eq. 1
Similarly,
Common difference =a3-a2
3k^2+4k+4-(2k^2+3k+6)
3k^2+4k+4-2k^2-3k-6
k^2+k-2 eq. 2
On equating eq. 1 and 2
2k^2-k-2=k^2+k-2
2k^2-k-2-k^2-k+2=0
k^2-2k=0
k(k-2)=0
k=0,k=2.
Pubali34:
very good
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