solve this maths quickly.
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Hi ,
It is given that ,
x = 2^1/3 + 2^2/3 ---( 1 )
do the cube both sides of the equation,
x³ = ( 2^1/3 + 2^2/3 )³
x³ = (2^1/3)³+(2^2/3)³+3(2^1/3)(2^2/3)(2^1/3+2^2/3)
[ ( a + b )³ = a³ + b³ + 3ab( a + b ) ]
x³ = 2 + 2² + 3 × 2 × x
x³ = 2 + 4 + 6x
x³ = 6 + 6x
x³ - 6x = 6
Hence proved.
I hope this helps you.
: )
It is given that ,
x = 2^1/3 + 2^2/3 ---( 1 )
do the cube both sides of the equation,
x³ = ( 2^1/3 + 2^2/3 )³
x³ = (2^1/3)³+(2^2/3)³+3(2^1/3)(2^2/3)(2^1/3+2^2/3)
[ ( a + b )³ = a³ + b³ + 3ab( a + b ) ]
x³ = 2 + 2² + 3 × 2 × x
x³ = 2 + 4 + 6x
x³ = 6 + 6x
x³ - 6x = 6
Hence proved.
I hope this helps you.
: )
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