Question

Solve this mcq and get points...

Answer 1

Hey mate,

pH = -log[H]

pH = 1 = -log[0.1 mol/L]

pH = 2 = -log[0.1/(X+1)]

0.1/(X+1) = 0.01

X=9

9 litres of water must be added in order to make an aqueous solution of HCl with a pH of 2.

Hope it helps!

Answer 2

$\huge{\boxed{\boxed{Hi Dear}}}$

$\huge{\mathfrak\red{Here \:is \:your \:answer}}$

$\huge{\mathcal\pink{Answer-}}$

$\huge{\boxed{\boxed{9L}}}$

pH = -Log [H]

pH = 1 = -Log [0.1 mol/ L]

pH = 2 = -Log [0.1/ (X + 1)]

0.1/ (X + 1) = 0.01

X = 9

9 Litre of water must be added in order to make an aqueous solution of HCI with a pH of 2.

$\huge{\mathcal\red{Hope \:it \:is \:helpful}}$

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