Solve this mod inequality
|x - 1| + |x² - 3x + 2|
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|x - 1| + |x² - 3x + 2|
= |x - 1| + |x² - 2x - x + 2|
= |x - 1| + |x (x-2) -1 (x-2)|
= |x - 1| + |(x-2) (x-1)|
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Answer:
Refer attachment
Value of x is 1 and interval of x is
1 < equal to x < 2
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