Question

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A car starts from rest and moves along the x-axis with constant acceleration of 5 m/s² for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from the rest?​

Answer 1

Given:

A car starts from rest and moves along the x-axis with a constant acceleration of 5 m/s² for 8 seconds.

To Find:

what distance will the car cover in 12 seconds since it started from rest.

Solution:

We know that,

$s = ut + \frac{1}{2}at^{2}$

But given that, the initial velocity is zero. Therefore, the distance covered by the car in first 8 seconds is

$s = 0 + \frac{1}{5} \times 5 \times {8}^{2}$

s = 180 metres

Therefore, the velocity attained at the end of 8 seconds is:

from, v = u + at

=>V= 0 + 5 x 8 40 m/s

Therefore, since the car has moved with constant velocity from 8th second to 12 second, the distance travelled is

S = v × t = 40 x 4 = 160 m.

Therefore, the total distance travelled is 160 + 160 = 320m.

Hope it helps :)

Answer 2

Answer:

A car starts from rest and moves along the x-axis with a constant acceleration of 5 m/s2 for 8 seconds. If it then continues with constant velocity what distance will the car cover in 12 seconds since it started from rest? s = v × t = 40 × 4 = 160 m .

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