Solve this my quadratic formula
(x-√2)^2 - 2(x-1) = 0
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Answer:
your answer is here
Step-by-step explanation:
= (x-√2)^2-2(x-1)= 0
= x^2+√2^2-2x+2=0.
= x^2+2-2x+2=0. (square and root will cancel)
= x^2-2x+4=0
this is your quadratic equation x^2-2x+4=0
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