solve this no. (ii) and advance thanxx
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Given 2 women + 5 Men can finish a work in 4 days.
Then their 1-day work = 1/4.
Given 3 women + 6 men finish it in 3 days.
Then their 1-day work = 1/3.
On solving (1) * 4, & (2) * 3, we get
8W + 20M = 1 ------- (3)
9W + 18M = 1 ----- (4)
On solving (3) * 9, (4) * 8, we get
72W + 180M = 9
72W + 144M = 8
-------------------------------
36M = 1
M = 1/36.
Therefore men alone can do 1/36th of the work in 1-day.
Therefore 1 men will take 36 days to finish the work.
Substitute M = 1/36 in (3), we get
8W + 20M = 1
8W + 20(1/36) = 1
8W + 20/36 = 1
8W = 1 - 20/36
8W = 16/36
W = 16/36 * 8
W = 16/288
W = 1/18.
Therefore women alone can do 1/18th of the work in 1-day.
Therefore woman will take 18 days to finish the work.
Hope this helps!
Then their 1-day work = 1/4.
Given 3 women + 6 men finish it in 3 days.
Then their 1-day work = 1/3.
On solving (1) * 4, & (2) * 3, we get
8W + 20M = 1 ------- (3)
9W + 18M = 1 ----- (4)
On solving (3) * 9, (4) * 8, we get
72W + 180M = 9
72W + 144M = 8
-------------------------------
36M = 1
M = 1/36.
Therefore men alone can do 1/36th of the work in 1-day.
Therefore 1 men will take 36 days to finish the work.
Substitute M = 1/36 in (3), we get
8W + 20M = 1
8W + 20(1/36) = 1
8W + 20/36 = 1
8W = 1 - 20/36
8W = 16/36
W = 16/36 * 8
W = 16/288
W = 1/18.
Therefore women alone can do 1/18th of the work in 1-day.
Therefore woman will take 18 days to finish the work.
Hope this helps!
siddhartharao77:
Gud luck!
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