Math, asked by abhinashkanta4p8lijc, 1 year ago

solve this no. (ii) and advance thanxx

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Answered by siddhartharao77
3
Given 2 women + 5 Men can finish a work in 4 days.

Then their 1-day work = 1/4.

Given 3 women + 6 men finish it in 3 days.

Then their 1-day work = 1/3.



On solving (1) * 4, & (2) * 3, we get

8W + 20M = 1   ------- (3)

9W + 18M = 1  ----- (4)


On solving (3) * 9, (4) * 8, we get

72W + 180M = 9

72W + 144M = 8

-------------------------------

              36M = 1

                  M = 1/36.

Therefore men alone can do 1/36th of the work in 1-day.

Therefore 1 men will take 36 days to finish the work.


Substitute M = 1/36 in (3), we get

8W + 20M = 1

8W + 20(1/36) = 1

8W + 20/36 = 1

8W = 1 - 20/36

8W = 16/36

W = 16/36 * 8

W = 16/288

W = 1/18.

Therefore women alone can do 1/18th of the work in 1-day.

Therefore woman will take 18 days to finish the work.



Hope this helps!

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