Question

solve this...... no spam​

Answer 1

Answer:

The angle of incidence and the angle of reflection is equal to each other so you can plus both the angles that

Explanation:

40+40=80 so the answer is 80

Answer 2

Required Answer:

${\underline {\underline {\boxed {\sf \pink { 80° } }}}}$

[ Please refer to the attachment for better understanding.]

So, here we have to find the measure of the angle between reflected ray and the incident ray.

We are given already:

• $\rm \blue { \angle \: of \: incidence \: (\angle \: i)= 40°}$

In order to find the measure of the angle between reflected ray and the incident ray, we also have to find out the measure of the angle of reflection.

So, as one of the laws of reflection implies that,

• Angle of incidence is equal to the angle of reflection.

$\sf { \therefore \angle \: i = \angle \: r }$

$\sf { \implies 40° =40°}$

So, the measure of angle of the reflection is 40°.

Now, the angle between reflected ray and the incident ray :–

• Angle of incidence + Angle of reflection

→ 40° + 40°

→ 80° ⠀⠀⠀[Answer]

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Extra!

Laws of reflection:

→ The incident ray, the reflected ray and the normal at the point of incidence lie on the same point.

→ The angle of incidence is equal to the angle of reflection.($\sf { \therefore \angle \: i = \angle \: r }$)

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