Question

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Answer 1

4(sin⁴30⁰ + cos⁴60⁰) - 3sin²45⁰ + 1 = 0

Putting the value of sin30⁰, cos60⁰ & sin45⁰ :-

4[(1/2)⁴ + (1/2)⁴] - 3(1/√2)² + 1 = 0

4[1/16 + 1/16] - 3 × 1/2 + 1 = 0

1/2 - 3/2 + 1 = 0

(1 - 3 + 2)/2 = 0

(3 - 3)/2 = 0

0 = 0

Answer 2

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